SOLUTION: LINEAR EQUATIONS A.Solve for the unknown in each equation. 4 - 3(t+2) + t = 5(t -1) -8t

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Question 1171895: LINEAR EQUATIONS
A.Solve for the unknown in each equation.
4 - 3(t+2) + t = 5(t -1) -8t

Found 2 solutions by Theo, MathTherapy:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
see my worksheet.



step 1:
i copied down the problem as it was displayed.

step 2:
i simplified as shown below.
-3 * (T + 2) became -3T - 6
5 * (T - 1) became 5T - 5

step 3:
i combined like terms as shown below.
4 - 6 became -2
-3T + T became -2T
5T - 8T became -3T

step 4:
i added 2T to both sides of the equation and i added 5 to both sides of the equation.
on the left, -2 + 5 became 3 and -2T + 2T became 0 and disappeared.
on the right, -3T + 2T became -T and -5 + 5 became 0 and disappeared.

step 5:
i multiplied both sides of the equation by -1.
on the left 3 became -3 and on the right -T became T.
i then switched sides to get T = -3.











Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!

LINEAR EQUATIONS
A.Solve for the unknown in each equation.
4 - 3(t+2) + t = 5(t -1) -8t
4 - 3(t+2) + t = 5(t -1) - 8t
4 - 3t - 6 + t = 5t - 5 - 8t
- 2t - 2 = - 3t - 5
- 2t + 3t = - 5 + 2

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