SOLUTION: The perimeter of a rectangular fields is 200m. If the length were reduced 20m and the width reduced by 25%, the perimeter would be reduced by 30%. The original length of the field
Question 1170798: The perimeter of a rectangular fields is 200m. If the length were reduced 20m and the width reduced by 25%, the perimeter would be reduced by 30%. The original length of the field is: Found 2 solutions by VFBundy, MathTherapy:Answer by VFBundy(438) (Show Source): You can put this solution on YOUR website! Original length = L
Original width = W
2L + 2W = 200
2(L - 20) + 2(0.75W) = 0.70(200)
2L - 40 + 1.5W = 140
2L + 1.5W = 180
1.5W = 180 - 2L
W = 180/1.5 - 2L/1.5
W = 120 - 2L/1.5
W = 120 - 4L/3
Plug W = 120 - 4L/3 into the first equation:
2L + 2W = 200
2L + 2(120 - 4L/3) = 200
2L + 240 - 8L/3 = 200
2L - 8L/3 = -40
6L/3 - 8L/3 = -40
-2L/3 = -40
-2L = -120
L = 60
Original length = L = 60m Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangular fields is 200m. If the length were reduced 20m and the width reduced by 25%, the perimeter would be reduced by 30%. The original length of the field is:
Let original length, be L
Then
We then get:
Original length, or