.
Let the slower car rate be x km/h;
then the faster car rate is (x+20) km/h.
The total distance equation is
4x + 4*(x+20) = 400 kilometers.
Simplify and find x
4x + 4x + 80 = 400
8x = 400 - 80 fa
8x = 320
x = 320/8 = 40.
ANSWER. The slower car rate is 40 km/h; the faster car rate is 40+20 = 60 km/h.
Solved.
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- Travel and Distance problems
- Travel and Distance problems for two bodies moving in opposite directions
- Travel and Distance problems for two bodies moving in the same direction (catching up)
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