SOLUTION: If K(-1, 2), L and N (1, -1) are vertices of angle KLN such that KLN=78.69°, KL intersects the axis at P, KL is produced. The inclination of KN is 0. The coordinates of M are (-3,

Question 1169770: If K(-1, 2), L and N (1, -1) are vertices of angle KLN such that KLN=78.69°, KL intersects the axis at P, KL is produced. The inclination of KN is 0. The coordinates of M are (-3, -5). Calculate
(a) The gradient of KN
(b) The size of 0, the inclination of KN
(c) Show that the gradient of KL is equal to 1
(d) Determine the equation of the straight line KL in the form of y=mx + c
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!

The assertion that

is the point

and

is the point

and the subsequent assertion that the inclination of

is zero, are mutually contradictory. In order for a segment to have an inclination of zero, the

-coordinates of the endpoints must be equal. Now if you meant that the inclination of

, you should have written: "The inclination of KN is theta". But I can only go on what you wrote. Repost this question spelling out things for which you cannot reproduce symbolically in plain text.

John

My calculator said it, I believe it, that settles it

From
I > Ø

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