SOLUTION: An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 5000 feet and Plane B is at an altitude of 4748 feet. Plane A is gaining altitude at 45.25

Question 1168100: An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 5000 feet and Plane B is at an altitude of 4748 feet. Plane A is gaining altitude at 45.25 feet per second and Plane B is gaining altitude at 50.5 feet per second.
How many seconds will pass before the planes are at the same altitude?
What will their altitude be when they're at the same altitude?
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
Altitude(A) = 5000ft + 45.25ft/sec * t
Altitude(B) = 4748ft + 50.5ft/sec * t

They will be at the same altitude when the two equations are equal:
4748 + 50.5t = 5000 + 45.25t

Solve for t: t=48sec
Plug t=48 into (A) or (B): Altitude(B)=7172ft

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