SOLUTION: Two pools are being filled with water. To start, the first pool contains 980 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20.25

Question 1168097: Two pools are being filled with water. To start, the first pool contains 980 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20.25 liters per minute. Water is being added to the second pool at a rate of 44.75 liters per minute.
After how many minutes will the two pools have the same amount of water?
How much water will be in each pool when they have the same amount?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
pool 1 has 980+20.25x, x=minutes
pool 2 is 44.75x
set them equal
980+20.25x=44.75x
980=24.5x
x=40 minutes
alternative way
the rate of change between the two is pool 2 is filling 24.5 liters per minute faster than pool 1. It has to catch up 980 liters. That will take 40 minutes.
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