SOLUTION: A European Swallow flies into the wind from the castle of Uther Penn Dragon to Camelot while carrying a coconut. He flies 28 miles to Camelot in 2 hours, delivers the coconut and

Question 1165883: A European Swallow flies into the wind from the castle of Uther Penn Dragon to Camelot while carrying a coconut. He flies 28 miles to Camelot in 2 hours, delivers the coconut and retrieves an identical coconut to carry back to the castle. He travels back the same distance (now with a tail wind) in 1.5 hours. What is the air speed of the laden swallow? What is the velocity of the wind?

Answer by ikleyn(52786) (Show Source): You can put this solution on YOUR website!
.


The effective rate flying against the wind is   = 14 miles per hour.

It is the difference of the groundspeed and the speed of the wind.



The effective rate flying back (with the wind) is   = 18  miles per hour.

It is the sum of the groundspeed and the speed of the wind.



Therefore, the groundspeed is half the sum of these values, which is 

*(18  + 14) = 16  mph.



The speed of the wind is half the difference of these values, which is 

*(18  - 14) = 2  mph.

Solved.

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It is a typical "tailwind and headwind" word problem.

See the lessons
    - Wind and Current problems
    - Wind and Current problems solvable by quadratic equations
    - Selected problems from the archive on a plane flying with and against the wind
in this site, where you will find other similar solved problems with detailed explanations.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the section "Word problems", the topic "Travel and Distance problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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