Let x be the largest number of medium sizes of which the outlet will have space. Then from the condition, you have this inequality x ++ <= 200. Multiply both sides by 6. You will get 6x + 3x + 2x <= 1200, 11x <= 1200 x <= = 109.09... ANSWER. The largest number of medium sizes of which the outlet will have space is 109, under given conditions.