SOLUTION: David is standing on top of a 30 m cliff overlooking a lake. He throws a rock up into the air and watches it land in the lake. The path of the rock can be modelled by the equation

Question 1164798: David is standing on top of a 30 m cliff overlooking a lake. He throws a rock up into the air and watches it land in the lake. The path of the rock can be modelled by the equation h(t) = - 4.9t2 + 6t + 30 where h is the height of the rock above the lake, in meters, t seconds after it was thrown.
(a) What is the maximum height that the rock reaches above the water?
(b) When does it reach its maximum height?
(c) How long after it was thrown does the rock hit the water?
(d) What is the height of the rock 2 seconds after it is thrown?
(e) When is the rock 10 m above the water?
(f) Determine the domain and range of the situation.
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.

In this site, there is a bunch of lessons on a projectile thrown/shot/launched vertically up
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform

Consider these lessons as your textbook, handbook, tutorials and (free of charge) home teacher.
Read them attentively and learn how to solve this type of problems once and for all.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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