SOLUTION: 10% of the oil in tank was drawn out and if the tank was originally 2/3 full what fraction of tank is now empty.?.

Question 1164328: 10% of the oil in tank was drawn out and if the tank was originally 2/3 full what fraction of tank is now empty.?.
Found 4 solutions by josgarithmetic, solver91311, jim_thompson5910, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

-----------still in the tank
----------empty in the tank

------------------------(wrong fraction drawn out )--------------------

----------------------amount now full

Amount of tank now EMPTY,
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

John

My calculator said it, I believe it, that settles it

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Let's say we had a tank that was 30 gallons in total capacity.
I'm picking on 30 because it is the LCD of the fractions 1/10 and 2/3
Note: 1/10 = 0.10 = 10%

If the tank is 2/3 full, then (2/3)*30 = 20 gallons of gas is in the tank
Then 10% of that amount (20 gallons) is taken out, meaning we take out 0.10*20 = 2 gallons of gas. We then have 20-2 = 18 gallons left.

The amount of empty space is 30-18 = 12 gallons

The fraction of empty space is 12/30 = (6*2)/(6*5) = 2/5

Answer: 2/5

The tutor @josgarithmetic has the right idea, but somehow got the 2/5 and 3/5 mixed up I think.

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

Originally, the tank was full. 10% of this volume was drawn out. It means that remaining OIL volume in the tank is - = = = of the full tank capacity. Hence, the tank is now 1 - = empty. ANSWER

------------

The solution and the answer by @josgarithmetic BOTH ARE WRONG.

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