SOLUTION: Katherine leaves home for school, riding her bicycle at a rate of 12miles/hr. Twenty minutes after she leaves, her mother sees Katherine's English paper on her bed and leaves to b

Question 1159607: Katherine leaves home for school, riding her bicycle at a rate of 12miles/hr. Twenty minutes after she leaves, her mother sees Katherine's English paper on her bed and leaves to bring it to her. If her mother drives at 36miles/hr, how far must she drive before she reaches Katherine?
Found 3 solutions by ikleyn, josgarithmetic, MathTherapy:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

Head start is 12 mph * of an hour = 4 miles. Speed approaching is 36-12 = 24 mph. Time to catch = of an hour = of an hour = 10 minutes. ANSWER

Solved.

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
20 minutes, same as ;
, four miles apart at the 'start'.

Mother's approach rate is mph.

x, time to catchup

Distance Mother traveled to catchup to Katherine:

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Katherine leaves home for school, riding her bicycle at a rate of 12miles/hr. Twenty minutes after she leaves, her mother sees Katherine's English paper on her bed and leaves to bring it to her. If her mother drives at 36miles/hr, how far must she drive before she reaches Katherine?

Let distance she should drive, be D
With , we get the following TIME equation:
3D - 12 = D ------ Multiplying by LCD, 36
- 12 = D - 3D
- 12 = - 2D
Distance to be driven, or
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