SOLUTION: Mr. Blackstone drove from his city hoe to his country house, stopping for lunch on the way. Before lunch, he traveled 80 miles farther than he did after lunch. Before lunch, he a

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Question 1155126: Mr. Blackstone drove from his city hoe to his country house, stopping for lunch on the way. Before lunch, he traveled 80 miles farther than he did after lunch. Before lunch, he averaged 40 mph, after lunch he averaged 50 mph. His traveling time, not including the time spent for lunch, was 6 1/2 hours. Find the number of miles he drove before lunch and also after lunch.
Answer by ikleyn(52763)   (Show Source): You can put this solution on YOUR website!
.

Let d be the distance traveled before lunch, in miles.


Then the distance traveled after lunch is d-80 miles.


He spent  hours for the first part  and  hours for the second part.


The total time equation is


     +  =  hours =  hours.


To solve it, multiply both sides by 200. You will get

    5d + 4*(d-80) = 1300.


Simplify and find d.


    9d = 1620.

     d =  miles = 180 miles.


Thus the partial distances are 180 miles and (180-80) = 100 miles, 

   and the total distance  is  180 + 100 = 280 miles.    ANSWER

Solved.


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