SOLUTION: Y=sin(2x+phi/3) Find The x-coordinate of the point A where the curve cuts the x axis

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Question 1153893: Y=sin(2x+phi/3)
Find
The x-coordinate of the point A where the curve cuts the x axis

Found 2 solutions by Cromlix, ikleyn:
Answer by Cromlix(4381)   (Show Source): You can put this solution on YOUR website!
Hi,
Where a curve cuts the x axis you make y = 0
Where a curve cuts the y axis you make x = 0
Y = sin(2x + pi/3)
sin(2x + pi/3) = 0
2x + pi/3 = 0, pi, 2pi, 3pi and 4pi (Extra angles due to presence of 2x)
2x = -pi/3, 2pi/3, 5pi/3, 8pi/3 and 11pi/3
x = -pi/6, pi/3, 5pi/6 4pi/3 and 11pi/6
I dont know your limits, but think it would be 0 <= x =<2pi
So A is liable to be pi/3.
Hope this helps. :-)

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

I came to make two notices.


First, "phi" in your condition is not "phi" ---- actually, it is "pi", instead. // Learn how to write it correctly (!)

    By the way, yesterday was National  (and International)  "pi-day" (!)


Second, I want to correct the answer by other tutor:

    if  0 <= x < 2*pi, then the solutions are these four values  x = , ,  and .


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