SOLUTION: Suppose that the equation 3bx^2 + 6bx = ax + 2a has two solutions for x and that the sum and the product of these solutions are equal, then b/a = ?

Question 1150727: Suppose that the equation 3bx^2 + 6bx = ax + 2a has two solutions for x and that the sum and the product of these solutions are equal, then b/a = ?
Answer by amarjeeth123(570) (Show Source): You can put this solution on YOUR website!
We are given that the equation 3bx^2 + 6bx = ax + 2a has two solutions for x and
the sum and the product of the roots are equal.
The given equation can be rewritten as 3bx^2+(6b-a)x+(-2a)=0
The sum of the roots=(a-6b)/3b
Product of the roots=(-2a)/3b
Since both of them are equal we get,a-6b=-2a
3a-6b=0
3a=6b
a=2b
b/a=1/2.
Verification:
Put b=1 and a=2
The equation becomes 3x^2+6x=2x+4
3x^2+4x-4=0
Sum of the roots=-4/3
Product of the roots=-4/3
Hence the solution is correct.
b/a=1/2.
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