SOLUTION: hi I need a help on this question. Can you please explain it if you continue the pattern 2 0 1 8 2 0 1 8 2 0 1 8 what would be the 2018th number? Thanks

Question 1149732: hi I need a help on this question. Can you please explain it
if you continue the pattern 2 0 1 8 2 0 1 8 2 0 1 8 what would be the 2018th number?
Thanks
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
.


Your sequence is PERIODIC.


The major period is these 4 terms {2 0 1 8}.


Divide 2018 by 4 to find the number of periods before 2018-th term


     = 504.5.


It means that there are 504 periods of 4 numbers before 2018-th term.


Exclude (mentally) these 504 periods.  504*4 = 2016.


Hence, the next two terms are 2 and 0 at 2017-th and 2018-th positions, respectively.


So, 0 is at the 2018-th position.     ANSWER

Solved, answered, explained and completed.

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