SOLUTION: Suppoise i have a coin collection of dimes and quarters containing 46 coins. If i have $6/70, how many of each type of coin do i have?

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Question 1147373: Suppoise i have a coin collection of dimes and quarters containing 46 coins. If i have $6/70, how many of each type of coin do i have?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
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Suppoise i have a coin collection of dimes and quarters containing 46 coins. If i have $6/70,
how many of each type of coin do i have?
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I see at least two errors in your post.

One of them is fatal and does not allow me to move forward.

Surely, I can make my assumptions on how to interpret your post,

but I don't want to make it in principle,

because it is YOUR RESPONSIBILITY to provide the correct input -- not my to "interpret" it.



Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


Algebraically....

d+q = 46
10d+25q = 670

Multiply the first equation by 10 and subtract the resulting equation from the second:
  10d + 25q = 670
  10d + 10q = 460
 -----------------
        15q = 210

Divide by 15 to find the number of quarters, q; then substitute in either of the original equations to find d.

You can do exactly the same calculations to solve the problem informally, without algebra:

(1) If all 46 coins were dimes, the value would be $4.60.
(2) The actual value is $6.70, which is $2.10, or 210 cents, more than $4.60.
(3) The difference between the value of a quarter and a dime is 15 cents.
(4) Divide 210 by 15 to find the number of quarters.
(5) Subtract the number of quarters from the total number of coins to find the number of dimes.

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