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The solution by tutor @rothauserc is not precisely correct, therefore I came to bring corrected solution.
Since the height of the building is given in feet, we will use 32 feet per second squared as the acceleration of gravity
distance(s) = 0.5 * at^2, where a is acceleration of gravity and t is the time it takes for the hammer to hit the ground
0.5 * 32 * t^2 = 300
t^2 = 300/16 = 18.75
t = 4.33 seconds
(a) average velocity(v) = = = 69.28 feet/sec <<<---=== my correction is in this line
(b) instantaneous velocity = at = 32 * 4.33 = 138.56 feet/sec