SOLUTION: Find the value of the standard normal random variable z, called z0 such that: P(−z0≤z≤0)=0.183 z0= P(−1.05≤z≤z0)=0.8008 z0=

SOLUTION: Find the value of the standard normal random variable z, called z0 such that: P(−z0≤z≤0)=0.183 z0= P(−1.05≤z≤z0)=0.8008 z0=

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Question 1138403: Find the value of the standard normal random variable z, called z0 such that:
P(−z0≤z≤0)=0.183
z0=
P(−1.05≤z≤z0)=0.8008
z0=

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
For the first, look for the probability being 0.0915 on each side, half of 0.183
rounded, that is 0.225 on each side
so p(-0.23 probability of z< -1.05 is 0.1575
so need to find ).8008 higher or z of 0.9583
That is z=+1.725 or +1.73
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