SOLUTION: Brown sold his car for 3/5 of the cost price and finds that in doing so he has lost £750.How much did he sell the car?

Question 1138116: Brown sold his car for 3/5 of the cost price and finds that in doing so he has lost £750.How much did he sell the car?
Found 2 solutions by ankor@dixie-net.com, Theo:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Brown sold his car foe 3/5 of the cost price and finds that in doing so he has lost £750.
How much did he sell the car?
:
let x = his original cost
he lost 2/5 of the original cost
x = 750
2x = 5*750
2x = 3750
x =
x = $1875 was the original cost
1875 - 750 = $1125 amt sold for
:
:
Check: * 1875 = $1125
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
he sold the car for 3/5 of the cost price and lost 750.

that means that 2/5 of the cost price must have been equal to 750.

that means that the cost of the car had to be 5/2 * 750 = 1875.

the cost of the car was 1875.

he sold it at 3/5 of the cost which would be 3/5 * 1875 = 1125.

he lost 1875 - 1125 = 750.

solution looks good.

solution is that he sold the car for 1125.

to solve using algebra, do the following.

let x = the cost of the car.

he sold the car for 3/5 * x and lost 750.

therefore 3/5 * x + 750 = x.

this means that 3/5 times the cost plus 750 equals the cost of the car.

subtract 3/5 * x from both sides of that equation to get 750 = x - 3/5 * x

simplify to get 750 = 2/5 * x

multiply both sides of this equation by 5/2 to get 750 * 5/2 = 2/5 * x * 5/2

simplify to get 750 * 5/2 = x

solve for x to get x = 5/2 * 750 = 1875.

the cost of the car is 1875.

he sold it for 3/5 * 1875 = 1125.

he lost 1875 - 1125 = 750.

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