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Let x = # of the 18 p volumes, y = # of 12 p volumes.
From the condition, you have these 2 equations
x + y = 120 (1) (counting volumes)
18*x + 12*y = 1920 (2) (counting money, in " p ")
From equation (1), express y = 120 - x and substitute it into equation (2), You will get
18x + 12*(120-x) = 1920.
Express x and calculate answer
x = = 80.
Then from equation (1), y = 120 - 80 = 40.
ANSWER. 80 volumes at 18p and 40 volumes at 12p.
CHECK. 80*18 + 40*12 = 1920 p. ! Correct !
The problem solved using 2-equation setup and the Substitution method.