SOLUTION: By the notation n (d) , we mean an n-digit number consisting of n times of the digit d. Thus 5(3) =555 and 4(3)9(5)8(1)3(6) =444999998333333. If 2(w)3(x)5(y)+3(y)5(w)2(x)=5(3)7(2)

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Question 1133951: By the notation n (d) , we mean an n-digit number consisting of n times of the
digit d. Thus 5(3) =555 and 4(3)9(5)8(1)3(6) =444999998333333. If 2(w)3(x)5(y)+3(y)5(w)2(x)=5(3)7(2)8(z)5(z)7(3) for some integers w, x, y and z, what is the value of w + x + y + z?
Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


You, or someone else, submitted this problem previously; I responded saying that the given conditions were impossible. I hoped when I saw the problem again that the statement of the problem had been corrected; but it was not. The problem still makes no sense as posed.

According to the given definition of n(d), the equation says the sum of two 10-digit numbers is equal to a 32-digit number:
                           wwxxxyyyyy
                         + yyywwwwwxx
     --------------------------------
     333332222222zzzzzzzzzzzzz3333333

Obviously, the sum of two 10-digit numbers can't be a 32-digit number.

So, just like last time, the problem can't be solved.
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