SOLUTION: By the notation n (d) , we mean an n-digit number consisting of n times of the digit d. Thus 3(5) =555 and 4(3)9(5)8(1)3(6) =444999998333333. If 2(w)3(x)5(y)+3(y)5(w)2(x)=5(3)7(2)

Question 1133317: By the notation n (d) , we mean an n-digit number consisting of n times of the
digit d. Thus 3(5) =555 and 4(3)9(5)8(1)3(6) =444999998333333. If 2(w)3(x)5(y)+3(y)5(w)2(x)=5(3)7(2)8(z)5(z)7(3) for some integers w, x, y and z, what is the value of w + x + y + z?
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

This might be an interesting problem... but you have messed up the definition of n(d).

You at first say that 3(5) means 555; but next you say 4(3) means 444.

If I try to make sense out of the problem, the equation you show seems to have the sum of two 10-digit numbers being equal to a 32-digit number....
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