SOLUTION: what are the real cube roots of 27/125 and 0.001?

Question 1131459: what are the real cube roots of 27/125 and 0.001?

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.

= . = 0.1.

It is the same as to ask how many is 2*2.

RELATED QUESTIONS
What are the real cube roots of −64, 0.001, and 27/125... (answered by ikleyn)
There are four 3-digit natural numbers, each of them equals the sum of the cube of its... (answered by Edwin McCravy)
What are the roots, both real and imaginary, of the equation... (answered by richard1234)
The roots of x^2+kx+9=0 are real and equal. What are the possible values of... (answered by monika_p)
How do you find the real or imaginary solutions of the equation 125^3-27=0? (answered by Alan3354)
Find the real roots of each equation. 25x^2-49=0 And 16x^2+8=9 And... (answered by nerdybill)
If the value of the discriminant for this equation is 0, what is the nature of the roots... (answered by TimothyLamb)
If arg((z-w)/(z-w^2)) =0,then prove that re(z)=-1/2,where (w and w^2 are non real cube... (answered by richard1234)
What are the three cube roots of -i. Express the roots in rectangular coordinates, and... (answered by ikleyn)