SOLUTION: Solve the system 2x^2-4xy+16y^2=2 3x+4y=3

Algebra.Com
Question 1131209: Solve the system
2x^2-4xy+16y^2=2
3x+4y=3
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
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Solve the system
2x^2-4xy+16y^2=2
3x+4y=3
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and you can find the y values corresponding to each of these x values.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Solve the system
2x^2-4xy+16y^2=2
3x+4y=3
Correct answers: 

What the other person has conjured up will NEVER get you these answers, since the correct equation is NOT 14x2 - 21x + 19 = 0.

 <======== WRONG, WRONG, WRONG

In other words, you DON'T have to finish anything since trying to finish will get you an answer that will be WRONG, all DAY LONG!! 

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