SOLUTION: Find the center and radius of the following circle: x2 + y2 - 12x + 8y - 29 = 0

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Question 1121380: Find the center and radius of the following circle:
x2 + y2 - 12x + 8y - 29 = 0

Found 3 solutions by josgarithmetic, MathLover1, Alan3354:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!





CENTER (6,-4)
RADIUS 9

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
to find the center and radius of the following circle, write given equation in this form:
where and are and coordinates of the center, and is the radius

......rearrange and group
.... complete squares

recall the rule:
since you have and , => for part
and and , => for part
than you have:






now you see that:
and and the center is at (, )
and the radius is

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find the center and radius of the following circle:
x2 + y2 - 12x + 8y - 29 = 0
-----
Complete the square for x and for y.
x^2 - 12x + y^2 + 8y - 29 = 0
x^2 - 12x + y^2 + 8y = 29
x^2 - 12x + 36 + y^2 + 8y + 16 = 29+36+16 = 81
(x-6)^2 + (y+4)^2 = 9^2
===============
(x-h)^2 + (y-k)^2 = r^2 is a circle - center at (h,k), radius r

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