SOLUTION: The product of two consecutive positive integers is 1 122. Find the two integers.
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Question 1120771: The product of two consecutive positive integers is 1 122. Find the two integers.
Found 2 solutions by solver91311, Alan3354:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent an integer. Then the next consecutive integer is, perforce, 
. The product of these two integers is 
Solve the factorable quadratic. There will be a positive root and a negative root, so that gives rise to two distinct answers to the question because negative numbers are included in the integers. Factoring hint: Since you multiplied two numbers that differ by only 1 to get the product 1122, the two numbers are going to be very close to the square root of 1122.
John
My calculator said it, I believe it, that settles it
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The product of two consecutive positive integers is 1 122. Find the two integers.
------
=~33.5
--> 33 & 34
===============
If you make a quadratic:
x^2 + x - 1122 = 0
then, to factor it, you have to find the 2 numbers.
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