Need help please.
I'm trying to figure out how to find three ordered pairs that satisfy the equation 4 + 2y = 3x.
I've been staring at this for a while, read, and researched, but cannot figure it out.
More than anything, I would like to understand how to get the intercepts, not just an answer.
Thank you!
4 + 2y = 3x
2y = 3x - 4 ----- Subtracting 4 from each side
------ Dividing by 2
Now, since the DENOMINATOR of the coefficient on x is 2, then the easiest and best values to substitute for x would be EVEN NUMBERS,
and better yet, 0 and other SMALL POSITIVE EVEN numbers, the likes of: 2, 4, and 6. This will give you 4 coordinates:
1)
This results in coordinate point: (0, - 2). This is also the y-intercept as x = 0.
2)
This results in coordinate point: (2, 1).
3)
This results in coordinate point: (4, 4).
4)
This results in coordinate point: (6, 7).
For the y-intercept, simply substitute 0 for x to find it. This was done above.
For the x-intercept, simply substitute 0 for y to find it, as follows:
4 + 2y = 3x
4 + 2(0) = 3x
4 = 3x
This results in coordinate point: .