SOLUTION: Find The sum of the first eight term of a linear sequence whose first term is 60 and whose last term is 46

Question 1118101: Find The sum of the first eight term of a linear sequence whose first term is 60 and whose last term is 46

Found 2 solutions by stanbon, greenestamps:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find The sum of the first eight term of a linear sequence whose first term is 60 and whose last term is 46
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Find The sum of the first eight term of a linear sequence whose first term is 60 and whose last term is 46
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S(8) = (8/2)(60+46) = 4(106) = 424
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Cheers
Stan H.
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Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

In a linear (arithmetic) sequence, the average of all the terms is the average of the first and last terms; in your problem the average is (60+46)/2 = 53.

Then since there are 8 terms, the sum of all the terms is 53*8 - = 424.
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