SOLUTION: Solve the system by back substitution.
2x+4y+z+3w=1
y+6z+2w=8
z+w= 2
2w= 6
The solution set is: _, _, _, _
Algebra.Com
Question 1117716: Solve the system by back substitution.
2x+4y+z+3w=1
y+6z+2w=8
z+w= 2
2w= 6
The solution set is: _, _, _, _
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
1. Solve the last equation for 
.
2. Substitute the value of you discovered in step 1 into the third equation and then solve for 
.
3. Substitute the value of from step 1 and the value of from step 2 into the second equation and then solve for 
.
4. Substitute the values of , 
, and from the first three steps into the first equation and solve for 
The way you are asking for the answer is incorrect. A list of the values of the four variables is NOT the solution set of the 4X4 system of equations. The solution set of this system has a single element, namely the ordered quadruple of the form )
. The solution set would then need to be written: \})
.
John
My calculator said it, I believe it, that settles it
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