If a^2 + 1 = a, then a^2 - a + 1 = 0. Multiply both sides by (a+1). You will get a^3 + 1 = 0, or a^3 = -1. So, the values of "a" that are the roots of the original equation, are the complex cubic roots of (-1). // If you solve the original equation using the quadratic formula, you will get the same result. Therefore, a^12 = (a^3)^4 = (-1)^4 = 1, and a^6 = (a^3)^2 = (-1)^2 = 1. Thus a^12 + a^6 + 1 = 1 + 1 + 1 = 3. The answer is 3. Choice b).