SOLUTION: An airplane travels 1200 miles in 4 hours with the wind. The return trip against the wind takes 5 hours. What is the wind speed and the speed of the airplane in still air?
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Question 1113103: An airplane travels 1200 miles in 4 hours with the wind. The return trip against the wind takes 5 hours. What is the wind speed and the speed of the airplane in still air? Found 2 solutions by ikleyn, Alan3354:Answer by ikleyn(52799) (Show Source):
The speed with the wind was
= 300 miles per hour.
It is the sum of the plane speed at no wind "u" and speed of the wind "v":
u + v = 300. (1)
The speed against the wind was
= 240 miles per hour.
It is the difference of the plane speed at no wind "u" and speed of the wind "v":
u - v = 240. (2)
Now add equations (1) and (2). You will get
2u = 300 + 240 = 540, which implies u = = 270 mph.
Now substitute it into eq(1) to get
v = 300 - 270 = 30.
Answer. The plain speed at no wind is 270 mph; the wind speed is 30 mph.
Solved.
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It is a typical "tailwind and headwind" word problem.
You can put this solution on YOUR website! An airplane travels 1200 miles in 4 hours with the wind. The return trip against the wind takes 5 hours. What is the wind speed and the speed of the airplane in still air?
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Find the 2 groundspeeds, upwind and downwind.
The plane's airspeed is the average of the 2.
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Windspeed = the difference between airspeed and groundspeed.