.
Let x be the width under the question.
Then the outer dimensions are 9+2x and 8+2x.
The condition says
(9+2x)*(8+2x) - 9*8 = 124 (the difference of the two areas is 124 square inches)
16x + 18x + 4x^2 = 124
34x + 4x^2 = 124
2x^2 + 17x - 62 = 0
= = .
The only positive root makes sense x = 2.75 (approximately).
Answer. 2.75 inches.
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To see other similar solved problems, look into the lessons
- Problems on the area and the dimensions of a rectangle surrounded by a strip
- Problems on a circular pool and a walkway around it
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic
"Dimensions and the area of rectangles and circles and their elements".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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Comment from student: Thank you for the help. I have a question though. Wouldn't -62 be put into the quadratic formula as 17^2-4(2)(-62)?
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My response: 17^2-4(2)(-62) = 17^2 + 4*2*62.