6|x-2| - 15 = -9*|x-2| + 15 ====> 6|x-2| + 9|x-2| = 15 + 15 ====> 15|x-2| = 30 ====> |x-2| = 2. The solutions are those "x" that are remoted at the distance of 2 units from the value of 2. These solutions are x= 0 and x= 4.