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The perimeter of a right triangle is 60 inches and the length of the altitude to the hypotenuse is 12 inches.
How many square inches are in the area of the triangle?
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Let x and y be the legs lengths.
Then the hypotenuse is .
The "perimeter" equation is
= 60, (1)
which implies
= 60 - (x+y),
= ,
= ,
2xy = 120*(x+y) - 3600,
xy = 60*(x+y) - 1800. (2)
From the other side, you have this equation expressing the area of the right-angled triangle
= ,
which gives
xy = . (3)
In this equation, replace in the right side by [60 - (x+y)], based on (2).
You will get instead of (3)
xy = 12*(60 - (x+y)). (4)
Now compare equations (2) and (4). Their left sides are identical; hence, right sides are equal:
60*(x+y) - 1800 = 12*(60 - (x+y)).
It implies 60*(x+y) + 12*(x+y) = 12*60 + 1800, or 72*(x+y) = 2520, and then x+y = = 35.
Thus we found that the sum of the leg lengths is 35 inches.
Then the hypotenuse is 60 - 35 = 25 inches (from the condition on the perimeter),
and the area of the triangle, which is under the question, is = 25*6 = 150 square inches.
SOLVED.
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By knowing that x+y = 35 and x^2 + y^2 = 25^2, it is easy to find the values of x and y individually.
At this level, it is just standard exercise in solving quadratic equations, and I leave it to you.