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Let x be the larger of the two numbers and y be the smaller.
Then the condition gives you these two equations
x = 7y + 19, (1)
3x = 11*(2y) + 19. (2)
Substitute (1) into (2). You will get
3*(7y + 19) = 22y + 19, or
21y + 57 = 22y + 19 ====> y = 57 - 19 = 38.
Then x = 7*y + 19 = 7*38 + 19 = 285.
Answer. The larger number is 285. The smaller number is 38.
Check. Check eq(1): 7*y+19 = 7*38+19 = 285 = x. ! Correct !
Check eq(2): 3x = 3*285 = 11*2*38+19 = 11*(2x)+19. ! Correct !
Thanks to @MathTherapy for pointing my error in the earlier version.