SOLUTION: An arrow is fired straight up from the ground with an initial velocity of 192 feet per second. Its height, s(t), in feet at any time t is given by the function s(t)=-16t^2+192t. Fi

Question 1095296: An arrow is fired straight up from the ground with an initial velocity of 192 feet per second. Its height, s(t), in feet at any time t is given by the function s(t)=-16t^2+192t. Find the interval of time for which the height of the arrow is greater than 252 feet.
Please show work.
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
s(t)=-16t^2+192t = 252
Solve for t.
It's at or above 252 ft between the 2 times.

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

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and also:

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The interval of time for which ft is
sec
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check:
here's the plot:

Looks about right
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