SOLUTION: The annual interest income on two investments is $79. Of the two investments, $200 more was invested at 5.5% than at 3%. How much was invested at 3%

Question 1094231: The annual interest income on two investments is $79. Of the two investments, $200 more was invested at 5.5% than at 3%. How much was invested at 3%
Answer by ikleyn(52792) (Show Source): You can put this solution on YOUR website!
.

Let x be the smaller investment, in dollars.

Then the larger investment is x+200 dollars.


Your equation (from the condition) is

0.03*x + 0.055*(x+200) = 79.


Multiply by 1000 both sides to get

30x + 55x + 11000 = 79000  ====>

85x = 79000-11000 = 68000  ====>  x =  = 800.


Answer.  $800 was invested at 3%  and  800+200 = $1000 was invested at 5.5%.

Solved.

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