SOLUTION: You randomly select 2 marbles from a mug containing 7 blue marbles, 3 red marbles, and 2 white marbles. How many times greater is the probability of selecting 2 red marbles when yo

Question 1089624: You randomly select 2 marbles from a mug containing 7 blue marbles, 3 red marbles, and 2 white marbles. How many times greater is the probability of selecting 2 red marbles when you replace the first marble before selecting the second marble than when you do not replace the first marble before selecting the second marble?

Found 2 solutions by math_helper, kelly22:
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
A = P(RR) without replacement = (3/12)*(2/11) = 6/132 = 2/44 = 1/22
B = P(RR) with replacement = (3/12)*(3/12) = 9/144 = 3/48 = 1/16
So B/A = (1/16)/(1/22) =
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8/4/17 - Edited to correct Pr(event A), I had 2/43 it should be 2/44=1/22.
Answer by kelly22(2) (Show Source): You can put this solution on YOUR website!
A = P(RR) without replacement = (3/12)*(2/11) = 6/132 = 1/22
B = P(RR) with replacement = (3/12)*(3/12) = 9/144 = 1/16
So B/A = (1/16)/(1/22) = 3.175
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