SOLUTION: A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 236 feet of fencing and does not fence the side along the street,

Question 1089557: A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 236 feet of fencing and does not fence the side along the street, what is the largest area that can be enclosed?
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
As the sample/the prototype see the solution of the similar problem in the lesson
    - A farmer planning to fence a rectangular area along the river to enclose the maximal area
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Finding minimum/maximum of quadratic functions".

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = the length of the side which is
perpendicular to the street
= the length of fence which is
parallel to the street
--------------------------
Let = the area of the lot

The formula for the vertex, which in this case
is a maximum is:

and

The maximum area is 6,962 ft2
-------------------------------
check:
Here's the plot:

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