SOLUTION: x-2 is a factor of x^2 -ax-8, what's the value of a? A)2 B)4 C)-4 D)-2

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Question 1088877: x-2 is a factor of x^2 -ax-8, what's the value of a?
A)2
B)4
C)-4
D)-2

Answer by ikleyn(52858)   (Show Source): You can put this solution on YOUR website!
.
The fact that (x-2) is a factor of  means that the polynomial

p(x) = 

has the root  x= 2  (the Remainder theorem).


In other words,  p(2) =  = 0.


It implies  4 - 2a - 8 = 0,  2a = 4 - 8 = -4,  a = -2.


Answer.  a = -2.  Option D).


The remainder theorem:
    1. The remainder of division the polynomial    by the binomial    is equal to the value    of the polynomial. 

    2. The binomial    divides the polynomial    if and only if the value of    is the root of the polynomial  ,  i.e.  .

    3. The binomial    factors the polynomial    if and only if the value of    is the root of the polynomial  ,  i.e.  .


See the lesson
    - Divisibility of polynomial f(x) by binomial (x-a) and the Remainder theorem
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Divisibility of polynomial f(x) by binomial (x-a). The Remainder theorem".


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