SOLUTION: The intensity (I) of a radio signal varies inversely as the square of the distance (d) from the transmitter. If the intensity is 23 W/m^2 at a distance from the transmitter of 2 km
Algebra.Com
Question 1088684: The intensity (I) of a radio signal varies inversely as the square of the distance (d) from the transmitter. If the intensity is 23 W/m^2 at a distance from the transmitter of 2 km, what is the intensity st a distance of 6 km?
Answer by mathmate(429) (Show Source): You can put this solution on YOUR website!
Question:
The intensity (I) of a radio signal varies inversely as the square of the distance (d) from the transmitter. If the intensity is 23 W/m^2 at a distance from the transmitter of 2 km, what is the intensity st a distance of 6 km?
Solution:
Given:
I(d)=k/d^2 => k=I(d)*d^2
23=k/2^2=k/4
Need I(6).
k=I(6)*6^2=23*2^2
Solve for I(6)
I(6)=(23*2^2)/6^2=23/9
= 2.56 approx.
Answer: the intensity at 6km is 2.56 W/m^2
RELATED QUESTIONS
inverse variation, direct variation, joint and combined
The intensity I of a... (answered by Nate)
The intensity of a TV signal varies inversely as the square of the distance from the... (answered by lwsshak3)
The intensity of a radio signal from the radio station varies inversely as the square of... (answered by Boreal,Alan3354)
I dont even know where to begin with solving this problem. Not sure of the formula.... (answered by stanbon)
The intensity I of a television signal varies inversely as the square of distance d from... (answered by Earlsdon)
The intensity of a radio signal from the radio station varies inversely as the square of... (answered by Fombitz)
The intensity 1, of light received from a source varies inversely as the square of the... (answered by josgarithmetic)
the intensity of light, l, received at a source varies inversely as the square of the the (answered by DrBeeee)
The intensity of a light varies inversely as the square of the distance from the light... (answered by ewatrrr)