SOLUTION: Jean is visiting her grandparents in Houston for 7 days. She wants to arrange a lunch with friends. If she picks a day at random, there is a 30% chance that all of her friends will
Algebra.Com
Question 1087905: Jean is visiting her grandparents in Houston for 7 days. She wants to arrange a lunch with friends. If she picks a day at random, there is a 30% chance that all of her friends will be available to meet for lunch. What is the probability that all her friends are available to meet for lunch on 4 different days?
a. 9.7%
b. 22.7%
c. 2.3%
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
This is a binomial distribution. You want the probability of exactly 4 successes in 7 trials where the probability of success on any given trial is 30%.
\ =\ {{n}\choose{k}} \left(p\right)^k\left(1\ -\ p\right)^{n-k})
\ =\ \frac{7!}{4!(7\ -\ 4)!}\ \cdot\ \left(0.3\right)^4\ \cdot\ \left(1\ -\ 0.3\right)^{7-4})
Just do the arithmetic.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
Jean is visiting her grandparents in Houston for 7 days. She wants to arrange a lunch... (answered by Boreal)
Paula eats lunch at a restaurant each day, and cannot change his easily, because she... (answered by ikleyn)
How many different ways can a visiting nurse visit 20 patients if she wants to see them... (answered by macston)
1.Juanita had $18 in her pocket. when she went to the mall with her friends , her lunch... (answered by ReadingBoosters)
Tammy carries an 8-oz. capacity water bottle to work with her during the day. Before she... (answered by GARGI)
Jasmine has $108 in savings. She already knows of an app subscription she wants to buy... (answered by ikleyn)
Paula invited 15 friends to his sweet 16 birthday party. She decided to use 16 small... (answered by Shin123)
a person planning her schedule for the day, has 5 places to go, in how many different... (answered by jim_thompson5910)
How many different ways can a visiting nurse see six patient if she is to visit most 3 of (answered by Sir226)