SOLUTION: An arrow is shot vertically with an initial speed of 25m/sec can be approximated by the function h(t)=-5t^2+25t where h(t) is the height of the arrow (in meters) and t is the time

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Question 1087514: An arrow is shot vertically with an initial speed of 25m/sec can be approximated by the function h(t)=-5t^2+25t where h(t) is the height of the arrow (in meters) and t is the time after release of the arrow (in seconds)
a) how high is the arrow after 2.5 secs?
b) how long does it take the arrow to return to the ground
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
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An arrow is shot vertically with an initial speed of 25m/sec can be approximated by the function h(t)=-5t^2+25t
where h(t) is the height of the arrow (in meters) and t is the time after release of the arrow (in seconds) 

a) how high is the arrow after 2.5 secs?                       - substitute t= 2.5 into h(t) and calculate.

b) how long does it take the arrow to return to the ground     - Find the positive root of the quadratic equation h(t) = 0.



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