SOLUTION: A chemist needs 2 liters of a 26% acid solution. He has an 18​% solution and a 50​% solution available to form the mixture. How much of each should be used to form the

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Question 1086591: A chemist needs 2 liters of a 26% acid solution. He has an 18​% solution and a 50​% solution available to form the mixture. How much of each should be used to form the 26​% ​solution?
Found 4 solutions by mathmate, josgarithmetic, josmiceli, MathTherapy:
Answer by mathmate(429)   (Show Source): You can put this solution on YOUR website!
Question:
A chemist needs 2 liters of a 26% acid solution. He has an 18​% solution and a 50​% solution available to form the mixture. How much of each should be used to form the 26​% ​solution?

Solution:

Given solutions at 18% and 50%, need 2L of 26%.
Ratio of 18%:50% = (50-26):(26-18) = 24:8 = 3:1 so 1.5L of 18% + 0.5L of 50%

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
x, volume of the 18%
2-x, volume of the 50%


-

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = liters of the 18% mixture needed
Let = liters of the 50% mixture needed
-----------------------------------------
(1)
(2)
-------------------------------
(2)
(2)
(2)
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)
------------------------


and
(1)
(1)
(1)
---------------------
1.5 liters of the 18% mixture are needed
.5 liters of the 50% mixture is needed
---------------------------------------
check:
(2)
(2)
(2)
(2)
(2)
OK

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
A chemist needs 2 liters of a 26% acid solution. He has an 18​% solution and a 50​% solution available to form the mixture. How much of each should be used to form the 26​% ​solution?
Correct answer: 
IGNORE anyone who says otherwise, and their RIDICULOUS answers!
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