SOLUTION: Please help me solve this (30x^3-8x^2-6x-3)/(5x+2) The answer should take the following form, such that q(x) is the quotient, r(x) is the remainder, and b(x) is the divisor.

Question 1085317: Please help me solve this
(30x^3-8x^2-6x-3)/(5x+2)
The answer should take the following form, such that q(x) is the quotient, r(x) is the remainder, and b(x) is the divisor.

Found 2 solutions by josgarithmetic, Theo:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

6x^2 -4x ___________________________________________ 5x+2 | 30x^3 -8x^2 -6x -3 | | 30x^3 12x^2 ------------------ 0 -20x^2 -6x -20x^2 -8x ---------------- 0 2x -3 2x ------------------

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
here's my worksheet.

first i divided 30x^3 by 5x to get 6x^2

then i multiplied (5x + 2) by 6x^2 to get (30x^3 + 12x^2)

then i subtracted (30x^3 + 12x^2) from (30x^3 - 8x^2) to get -20x^2

then i brought down -6x to get (-20x^2 - 6x)

then i divided -20x^2 by 5x to get -4x

then i multiplied (5x + 2) by -4x to get (-20x^2 - 8x)

then i subtracted (-20x^2 - 8x) from (-20x^2 - 6x) to get 2x

then i brought down -3 to get (2x - 3)

then i divided 2x by 5x to get 2/5

then i multiplied (5x + 2) by 2/5 to get (2x + 4/5)

then i subtracted (2x + 4/5) from (2x - 3) to get -19/5

then i stopped because the degree of -19/5 is less than the degree of 5x + 2

-19/5 is the remainder and is written as -(19/5) / (5x + 2)

the dividend is the original expression of 30x^3 - 8x^2 - 6x - 3

the divisor is 5x + 2

the quotient is the result of the division and is 6x^2 - 4x + 2/5 - (19/5) / (5x + 2)

here's a tutorial on how to do long division.

http://www.mesacc.edu/~scotz47781/mat120/notes/divide_poly/long_division/long_division.html

here's an online long division calculator that gives you the same result.

http://www.emathhelp.net/calculators/algebra-1/polynomial-long-division-calculator/

here are the inputs to and outputs from this calculator

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