SOLUTION: a man invests a certain amount of money at 2% interest and $800 more than that amount another account at 4% interest. At the end of one year, he earned $92 in interest. How much mo
Algebra.Com
Question 1080608: a man invests a certain amount of money at 2% interest and $800 more than that amount another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x at 2%
x+800 at 4%
.02x+.04(800+x)=92
.06x+32=92
.06x=60
multiply both sides by 100
6x=6000
x=$1000@2@=$20.
x+800=$1800@4%=$72
Total is $92.
RELATED QUESTIONS
A man invests a certain amount of money at 2% interest and $800 more than that amount in... (answered by palanisamy)
A man invests a certain amount of money at 2% interest and $800 more than that amount in... (answered by checkley77)
A man invests a certain amount of money at 2% interest and $800 more than that amount in... (answered by fractalier)
A man invests a certain amount of money at 2% interest and $800 more than that amount in... (answered by Boreal)
A man invest a certain amount of money at 2% interest and $800 more than that amount in... (answered by Boreal,stanbon)
Desa invested a certain amount of money at 4% interest and $1500 more than that amount at (answered by checkley71)
Desa invested a certain amount of money at 4% interest and $1500 more than that amount at (answered by solver91311)
Desa invested a certain amount of money at 2% interest and $12000 more than that amount... (answered by stanbon)
Eva invested a certain amount of money at 7% interest and $1400 more than that amount at... (answered by stanbon)