SOLUTION: if 2log5(2x-y)=log5 xy^2 - log5 y , find x/y (5 = base)

Algebra.Com
Question 1080330: if 2log5(2x-y)=log5 xy^2 - log5 y , find x/y
(5 = base)

Answer by Edwin McCravy(20063)   (Show Source): You can put this solution on YOUR website!
 

 

 

 

 

 

 

 



However, such equations often have extraneous 
answers, so we must check.  Logarithms may
be taken only of positive numbers.

Checking






We can see that on the left side, x must be negative 
to insure that a logarithm is being taken only of a 
positive number.  However that causes both terms on 
the right to be logarithms of negative numbers. 

So we must discard 

Checking 









Which checks.

The only solution is 

Edwin

RELATED QUESTIONS

Simplify 1/3(log5 x – log5 3 + 2log5 y). (answered by lwsshak3,stanbon)
If 2 log5 (x+y) = 1 + log5 x + log5 y, show that x^2+y^2 =... (answered by josmiceli)
log5 Y^2 + log5 Y^0.5 =... (answered by ankor@dixie-net.com)
2Log5^x +... (answered by fractalier)
How do you write log5 y - 4(log5 r + 2log5 t) as a single... (answered by Alan3354)
How do you condense this? 1/2(log5(x)+log5(y))-2... (answered by LinnW)
Log5 (y+ 1) - log5 8 = log5 (y- 3) - log5... (answered by ewatrrr)
Condense the expression. 1/3 log5 8-1/2 log5 x = 4 log5... (answered by Alan3354)
Show that log5 xy = 2 log25 x + 2 log25 y. Hence or otherwise, find the values of x and y (answered by Theo)