.
For the number of oranges per one tree, "n", as the function of the number of trees per acre, "t", the condition gives this formula:
n = 630 - 15*(t-20).
Then the number of oranges per acre is
O(t) = n*t = t*(630 - 15*(t-20)) = 630t - 15t^2 + 300t = -15t^2 + 930t.
They ask to find the maximum of this quadratic function of t.
From the general theory, the maximum is achieved at t = = = = 31.
So, 31 tree per acre provide the maximal total number of oranges per acre.
This maximum is equal to O(31) = 31*(630-15*(31-20)) = 31*(630-15*(-11)) = 21*(630+15*11) = 16695.
Answer. 31 trees per acre provide the maximal number of oranges of 16695.
*** Solved ***
Plot y = t*(630 - 15*(t-20))
On finding the maximum of a quadratic function and associated solved problems see the lessons
- HOW TO complete the square to find the minimum/maximum of a quadratic function
- Briefly on finding the minimum/maximum of a quadratic function
- HOW TO complete the square to find the vertex of a parabola
- Briefly on finding the vertex of a parabola
- Using quadratic functions to solve problems on maximizing revenue/profit
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Finding minimum/maximum of quadratic functions".