SOLUTION: A shipment of 50 television sets contains 3 defective units. How many ways can a vending company buy three of these units and receive no defective units?
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Question 1077465: A shipment of 50 television sets contains 3 defective units. How many ways can a vending company buy three of these units and receive no defective units? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! One way is 47/50*46/49*45/48 and multiply by the number of possible ways to choose 3, which is 50C3.
A little better way is to say there are 47 good ones and you want to know how many ways you can choose from 47.
47C3=16215 ANSWER
Using the probability above, unrounded, (rounded is 0.8273), 16215 is again reached.
