SOLUTION: Kenneth invested some money at 4% and $7000 less than twice that amount at 9%. If x represents the amount invested at 4%, how much was invested for the two investments?

SOLUTION: Kenneth invested some money at 4% and $7000 less than twice that amount at 9%. If x represents the amount invested at 4%, how much was invested for the two investments?

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Question 1074296: Kenneth invested some money at 4% and $7000 less than twice that amount at 9%. If x represents the amount invested at 4%, how much was invested for the two investments?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
If x is the amount invested at 4%, then the amount invested at 9% would be 2x-7000. So, for the two investments:x+2x-7000= 3x-7000 as the total amount invested. ☺☺☺☺
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